![]() Similarly, the boost::datetime library provides good high-resolution timing classes that should be highly portable. Since C++11, there are much better timing facilities available that offer better resolution in a form that should be very portable across different compilers and operating systems. Linux), then the clock_gettime() function is a good choice. If one is content to limit oneself to POSIX platforms (e.g. The only fully portable C function that may provide better resolution appears to be clock(), but that measures processor time rather than wallclock time. Printf ("gettimeofday:: Elasped time is %lf nanoseconds.\n", diff/10 ) Īs others have already noted, the time() function in the C standard library does not have a resolution better than one second. Printf ("clock_gettime:: Elasped time is %lf nanoseconds.\n", diff/10 ) Äiff+= double( (t2.tv_usec)*1000) Printf ("high_resolution_clock:: Elasped time is %lf nanoseconds.\n", diff/10 ) Äiff+= double( ts2.tv_nsec - ts1.tv_nsec ) High_resolution_clock::time_point t1, t2 Printf ("Elasped time is %lf nanoseconds.\n", dif ) Äouble dif = double( ts2.tv_nsec - ts1.tv_nsec ) Äouble dif = double( (t1.tv_usec)*1000) High_resolution_clock::time_point t2 = high_resolution_clock::now() Äouble dif = duration_cast( t2 - t1 ).count() High_resolution_clock::time_point t1 = high_resolution_clock::now() the actual working code here,I have just put a delay function If (seconds<(60*60*24)) // a day is not overÄss = fmod(seconds,60) // the remainder is seconds to be displayedįloat minutes= seconds/60 // the total minutes in floatÄmm= fmod(minutes,60) // the remainder are minutes to be displayedįloat hours= minutes/60 // the total hours in floatÄ®lse // we have reached the counting of daysÄmm= fmod(minutes,60) // the rmainder are minutes to be displayedÄhh= fmod (hours,24) // the hours to be displayedĬout<<"Count Is : "<<count<<"Time Elapsed : "<<ddays<<" Days "<<dhh<<" hrs "<<dmm<<" mins "<<dss<<" secs" Int loopcount = 1000 // just for demo your loop will be different of courseįor(float count=1 count ![]() i am first trying to display time elapsed every time loop runs Now your time spanning loop or code goes here +My attempt to build a benchmarking framework based on chrono is recorded here + This is why the forwarded function call. Std::cout << "Average run time " << avg.count() << " ms\n" average: auto avg = (measure::duration(func) + measure::duration(func)) / 2 count() is most useful for clients that want to post-process a bunch of durations prior to I/O, e.g. Return std::chrono::duration_cast(ClockT::now()-start) Īs mentioned in (1), using the duration w/o. Std::invoke(std::forward(func), std::forward(args).) Say you have a function F invokable with arguments arg1,arg2, this technique results in: cout ::duration(F, arg1, arg2).count() 2 - InstrumentationĪny callable (function, function object, lambda etc.) can be instrumented for benchmarking. When we just do IO, we use the count() or ticks of a duration (e.g. here this means using std::chrono::milliseconds). Return std::chrono::duration_cast(_end - _start) Īs Howard Hinnant pointed out, we use a duration to remain in the chrono type-system and perform operations like averaging or comparisons (e.g. Timep_t _start = ClockT::now(), _end = & "toc before reporting") Using timep_t = typename ClockT::time_point Use a timer based on std::chrono: Timer clock // Timer Return std::chrono::duration_cast(clock_t::now() - start) Use a delta function to compute time differences: auto start = std::chrono::steady_clock::now() Īuto since(std::chrono::time_point const& start)
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